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" ... for the second term, and the other for the first. III. finally, multiply the second and third terms together, divide the product by the first, and the quotient will be the answer in the same denomination as the third term. "
The handy book of arithmetic, by a schoolmaster - Page 45
by Handy book - 1861
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Mathematics: Compiled from the Best Authors and Intended to be the ..., Volume 1

1801 - 446 pages
...terms of supposition and demand, and the second of the same kind with the answer required. 2. Bring 3. Multiply the second and third terms together, divide the product by the first, and the quotient will be the answer. NOTE 1. 2. Bring the first and third numbers into the same denomination,...
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The Scholar's Arithmetic; Or, Federal Accountant ...: The Whole in a Form ...

Daniel Adams - 1807 - 248 pages
...first; but, if less, place the greater for the first, and the remaining one for the second term. 2. Multiply the second and third terms together, divide the product by the first, and the quotient will be the answer. EXAMPLES. 1. If 30 horses plough 12 acres, how many will 40 plough...
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The Federal Arithmetic; Or, A Compendium of the Most Useful Rules of that ...

James Noyes - 1808 - 168 pages
...it, the first term ; and that which is of the same name with the answer required, the second term. 2. Multiply the second and third terms together, divide the product by the first, and the quotient will be the answer. Note \ , Whefi the second term consists of more than one denomination,...
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The Arithmetical Catechism, Compiled from Various Authors, for the Use of ...

Henry Jackson - 1824 - 172 pages
...first, but if less, place the greater for the first, and the remaining one for the second term, mult-ply the second and third terms together, divide the product by the first, and the Quotient ke tbe aatwer. EXAMPLES. I. If 95yds. of cloth cost $80, how many yds. can I buy for...
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The Complete Mathematical and General Navigation Tables: Including ..., Volume 1

Thomas Kerigan - 1828 - 776 pages
...and third terms into the same name, and the second into the highest denomination mentioned. — Then, Multiply the second and third terms together ; divide the product by the first term, and the quotient will be the answer in the same denomination as the second number; — observing, however,...
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A Short System of Practical Arithmetic: Compiled from the Best Authorities ...

William Kinne - 1829 - 246 pages
...less, write the lew of the two remain^ ing 'numbers in the third place, and the other in the first. Multiply the second and third terms together, divide the product by the first, and the quotient will be the answer. NOTE 1. — 1t is sometimes most convenient to multiply and divide...
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The Complete Mathematical and General Navigation Tables: Including Every ...

Thomas Kerigan - 1838 - 804 pages
...and third terms into the same name, and the second into the highest denomination mentioned. — Then, Multiply the second and third terms together ; divide the product by the first term, and the quotient will be the answer in the same denomination as the second number; — observing, however,...
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Adams's New Arithmetic: Arithmetic, in which the Principles of Operating by ...

Daniel Adams - 1838 - 276 pages
...the two remaining numbers for the second term, and the greater for the fin,t ; and, in either case, multiply the second and third terms together, »;•« divide the product by the first for the sns'.vei, which will always be of the same denomination as (be third term. Note 1. If the first...
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The Western Practical Arithmetic: Wherein the Rules are Illustrated, and ...

1838 - 218 pages
...till they are ; and if the third term cons of several denominations, reduce it to the lowest. Then multiply the second and third terms together, divide the product by the ßrst term, the quotient be the answer or fourth term. ГОТЕ. — The answer will be of that denomination...
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Practical Arithmetic, Uniting the Inductive with the Synthetic Mode of ...

James Bates Thomson - 1846 - 354 pages
...the other two numbers for the second term, and t/ce other for the first. III. Finally, multiplying the second and third terms together, divide the product by the first, and the quotient will be the answer in the same denomination as the third term. PROOF. — Multiply...
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