The Analyst: A Monthly Journal of Pure and Applied Mathematics, Volumes 3-4Pierson & Blair, 1876 |
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Page 27
... locus of the middle point of the opposite side , in rectangular coordinates . " SOLUTION BY CHRISTINE LADD , UNION SPRINGS , N. Y. We have the following equations from which to determine the relation between 2 and if the origin is at ...
... locus of the middle point of the opposite side , in rectangular coordinates . " SOLUTION BY CHRISTINE LADD , UNION SPRINGS , N. Y. We have the following equations from which to determine the relation between 2 and if the origin is at ...
Page 28
... locus , or 4y2 + 4x2 4ax = 4b2 + 4d2 — — 2a2 — y2 + ( x — fa ) 2 = b2 + d2 — { ( a2 + c3 ) . Consequently the locus is a circle , whose centre is the middle point of the side AB , and whose radius = 1 / [ b2 + ď3 — ( a2 + c2 ) ...
... locus , or 4y2 + 4x2 4ax = 4b2 + 4d2 — — 2a2 — y2 + ( x — fa ) 2 = b2 + d2 — { ( a2 + c3 ) . Consequently the locus is a circle , whose centre is the middle point of the side AB , and whose radius = 1 / [ b2 + ď3 — ( a2 + c2 ) ...
Page 31
... locus of the intersection of these tangents . 102. BY G. W. Hill . - Prove that in every triangle the square of the sum of the squares of the sides exceeds double the sum of their fourth powers . 103. Through two given points draw a ...
... locus of the intersection of these tangents . 102. BY G. W. Hill . - Prove that in every triangle the square of the sum of the squares of the sides exceeds double the sum of their fourth powers . 103. Through two given points draw a ...
Page 42
... locus while the system changes its shape , or undergoes de- formation . Thus a jointed quadrilateral is a linkage ; if two bars jointed to gether have their free ends jointed one to each of two bars , the system becomes a six - bar ...
... locus while the system changes its shape , or undergoes de- formation . Thus a jointed quadrilateral is a linkage ; if two bars jointed to gether have their free ends jointed one to each of two bars , the system becomes a six - bar ...
Page 60
... locus of any point in the line DC . — 8 ) — 712 ( a + s ) — 2s ( a2 — s2 — c2 ) ] 2 = 0 , = When P is the middle point , we have merely to make 80 in our equa- tion , giving : - 2.2 - 4 ( x2 + y2 ) 2 + 4 ( 2a2 — 2c2 — p2 — r / 2 ) x + 4 ...
... locus of any point in the line DC . — 8 ) — 712 ( a + s ) — 2s ( a2 — s2 — c2 ) ] 2 = 0 , = When P is the middle point , we have merely to make 80 in our equa- tion , giving : - 2.2 - 4 ( x2 + y2 ) 2 + 4 ( 2a2 — 2c2 — p2 — r / 2 ) x + 4 ...
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Common terms and phrases
5th degree a₁ algebraic ANALYST angle ARTEMAS MARTIN assumed axis b₁ C₁ circular coefficients common logarithms constant curve denote determine differential distance E. B. SEITZ ellipse Elliptic Functions equal equation expression factor formula function given circle gives hence hyperbola integral intersection inverse Lagrange's Theorem locus logarithms method multiply observations orbital orbital force ORSON PRATT oxen parabola parallel perpendicular plane points at infinity position probable error quadrics quadrilateral radius ratio reduce represent result roots sides SOLUTION BY PROF SOLUTIONS of problems sphere square substitution surface tangent Taylor's Theorem Theorem tion triangle UNION SPRINGS unknown quantities values velocity whence zero