## The Principles of the Solution of the Senate-house 'riders,' Exemplified by the Solution of Those Proposed in the Earlier Parts of the Examinations of the Years 1848-1851Macmillan & Company, 1851 - 116 pages |

### From inside the book

Results 1-5 of 18

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**vertical**angle of the cone ; that is , when BF is perpendicular to DE . Hence the angle between the asymptotes will be greatest when the cutting plane PAR is parallel to the axis of the cone , and that angle will be equal to the**vertical**... Page 43

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**vertical**plane passing through the summit , and the summit ( S ) is ob- served from the further station , but a lower point ( S ) is observed by mistake from the nearer , shew that the height determined by the process lies between the ... Page 45

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**vertical**wall , by means of a fine string attached to the lower end of the rod and to a point in the wall . Find by geometrical construction the point in the wall to which the string must be attached . Let AB ( fig . 33 ) be the rod ... Page 49

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**vertical**through the centre of gravity G ( fig . 37 ) of the triangle meet the given line through A in O , and the base of the triangle in M. Then , in the limiting case of equi- librium , OB must be the direction of the resultant of ... Page 50

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**vertical**planes inclined at a given angle , touch each other in the line bisecting the angle . Find the radius of the least disk which may be pressed between them without causing them to separate . The mutual pressure of two smooth ...### Other editions - View all

The Principles of the Solution of the Senate-House 'Riders: Exemplified by ... Francis J. Jameson No preview available - 2018 |

The Principles of the Solution of the Senate-House 'Riders: Exemplified by ... Francis J. Jameson No preview available - 2015 |

### Common terms and phrases

AC² AN.NM Arithmetic arithmetical progression axis bisects body C₁ Cambridge centre of gravity chord CHURCHILL BABINGTON circle cloth cone Conic Sections conjugate hyperbola constant curvature curve cycloid describe diameter direction directrix distance drawn Edition ellipse equations equilibrium Fellow of St fluid focus geometrical given point Hence horizontal hyperbola inches inclined inscribed John's College joining latus-rectum least common multiple Lemma length locus meet mirror move number of seconds oscillation parabola parallel parallelogram particle perpendicular plane polygon pressure prop proportional proposition prove pullies quadrilateral quantity radius ratio rays rectangle refraction right angles sewed shew sides specific gravity spherical square straight line string surface tan² tangent triangle ABC Trinity College tube V₁ vary vertex vertical W₁ weight

### Popular passages

Page 4 - To divide a given straight line into two parts, so that the rectangle contained by the whole and one of the parts, shall be equal to the square of the other part.

Page 6 - The angle at the centre of a circle is double of the angle at the circumference upon the same base, that is, upon the same part of the circumference.

Page 11 - AB is a diameter, and P any point in the circumference of a circle; AP and BP are joined and produced if necessary ; if from any point C of AB, a perpendicular be drawn to AB meeting AP and .BP in points D and E respectively, and the circumference of the circle in a point F, shew that CD is a third proportional of CE and CF.

Page 9 - IF the angle of a triangle be divided into two equal angles, by a straight line which also cuts the base; the segments of the base shall have the same ratio which the other sides of the triangle have to one another...

Page 4 - In any right-angled triangle, the square which is described upon the side subtending the right angle, is equal to the squares described upon the sides which contain the right angle.