The Principles and Practice of Statics and Dynamics, Embracing a Clear Development of Hydrostatics, Hydrodynamics, and Pneumatics: With Central Forces and Super-elevation of Exterior Rail ; for the Use of Schools and Private StudentsWeale, 1851 - 148 pages |
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The Principles and Practice of Statics and Dynamics, Embracing a Clear ... Thomas Baker No preview available - 2018 |
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accelerating force acquired in falling angle axis beam body be projected centre of gravity centrifugal force centripetal force circumference column cord cubic foot curve cwts density depth descend diameter direction distance draw earth elastic embankment equal equilibrium exterior rail feet per second fluid force of gravity force or weight forces acting formulæ friction fulcrum given hence inches inclined plane indefinitely small length lever mercury miles per hour moment of inertia motion moveable pulley number of forces orifice parabola parallel parallelogram particle pendulum perpendicular piston PROB PROP.-If PROP.-To find proportional pump radii radius railway rest resultant screw shewn specific gravity steam engine surface tension three forces tion tons train triangle units valve velocity acquired vessel wall wheel and axle whence whole
Popular passages
Page 135 - ... Their distances, according to Kepler and Bullialdus, scarcely differ by any sensible quantity, and where they differ most the distances drawn from the periodic times fall in between them. That the circum-terrestrial force likewise decreases in the duplicate proportion of the distances, I infer thus. The mean distance of the moon from the centre of the earth, is, in semi-diameters of the earth, according to...
Page 93 - Prove that the pressure of a uniform heavy incompressible fluid on any surface is equal to the weight of a column of the fluid, the base of which is equal to the area of the surface, and altitude equal to the depth of the centre of gravity of the surface below the surface of the fluid.
Page 105 - To explain the construction of the common barometer, and to shew that the mercury is sustained in it by the pressure of the air on the surface of the mercury in the basin.
Page 20 - AB, joining them, may be perpendicular to the line joining the centre of gravity g with the point of support m. In a perfect balance all the parts must be symmetrical with respect to the fulcrum c; that is, the parts on either side of this point must be exactly equal. Moreover, the scales must be in equilibrium when empty, and there must be as little friction as possible at the fulcrum c. 51 . The False Balance. — This balance has its arms of unequal length, and is in equilibrium when charged with...
Page 14 - A Lever is an inflexible rod moveable only about a fixed axis ; which is called the fulcrum. The portions of the lever into which the fulcrum divides it are called the arms of the lever: when the arms are in the same straight line, it is called a straight lever; in other cases a bent lever.
Page 92 - M perpendicular to the plane of that area, and equal to the weight of the vertical column pq, the base of which is q r. The pressure exerted on qr perpendicularly, is equal to the weight of the fluid pr ; let P = perpendicular pressure on qr, and W = weight of the fluid pr ; take qd = pq to represent the perpendicular pressure of any particle against qr; then this pressure may be resolved into two eq,fq; and eq is the part of the pressure which acts perpendicularly ; and since qr is indefinitely...
Page 86 - ... particle by the square of its distance from the centre line. As the stress upon the extreme or most remote particle in a section will be less for a given moment of resistance the deeper the beam is, the flexure of the beam will vary inversely as the summation last spoken of. This summation of the area of each particle, multiplied by the square of its distance from the centre line, is known as the moment of inertia of the section, and is denoted by I. It may be obtained from the moment of resistance,...
Page 62 - R and r the radii of the greater and less ends in the conic frustum, or the sides of the two ends in any regular pyramid. 116. In the paraboloid the distance of the centre of gravity from the vertex is •§• of the axis. 117. In the frustum of the paraboloid, the distance on the axis from the centre of the less end is...
Page 27 - In a system of toothed wheels and axles, it is required to find the relation between the power and the weight, when they are in equilibrium.
Page 60 - CM : Cm :: BM : bm, and AM = BM, therefore am = bm ; hence the line ab will balance itself on C M. Similarly every other line parallel to AB will be in equilibrium on CM ; therefore the whole triangle ABC will balance itself on CM, and consequently the centre of gravity of the triangle is in C M. In like manner it may be proved that the centre of gravity of the triangle is in the line BN; therefore G the point of intersection of CM, BN is the centre of gravity of the triangle. Join MN; then, since...