THEOREM XVI (12). The equal Ordinates, or the Ordinates at equal Distances from the Centre, on the opposite Sides and Ends of an Hyperbola, have their Extremities connected by one Right Line passing through the Centre, and that Line is bisected by the Centre. For, when CD = CG, then also is DE = GH by cor. 2 theor. 1. But the ∠D=∠G, being both right angles; therefore the third side CE = CH, and the DCE = GCH, and consequently ECH is a right line. Coral. 1. And, conversely, if ECH be a right line passing through the centre; then shall it be bisected by the centre, or have CE = CH; also De will be = GH, and CD = CG. Corol. 2. Hence also, if two tangents be drawn to the two ends E, H of any diameter EH; they will be parallel to each other, and will cut the axis at equal angles, and at equal distances from the centre. For, the two CD, CA being equal to the two co, cb, the third proportionals cr, cs will be equal also; then the two sides ce, CT being equal to the two cH, cs, and the included angle ECT equal to the included angle Hcs, all the other corresponding parts are equal: and so the LT=∠s, and TE parallel to Hs. Corol. 3. And hence the four tangents, at the four extremities of any two conjugate diameters, form a parallelogram inscribed between the hyperbolas, and the pairs of opposite sides are each equal to the corresponding parallel conjugate diameters. For, if the diameter eh be drawn parallel to the tangent Te or Hs, it will be the conjugate to EH by the definition; and the tangents to eh will be parallel to each other, and to the diameter EH for the same reason. THEOREM XVII (13). If two Ordinates ED, ed be drawn from the Extremities E, e, of two Conjugate Diameters, and Tangents be drawn to the same Extremities, and meeting the Axis produced in T and R; Then Then shall CD be a mean Proportional between cd, dr, and cd a mean Proportional between CD, DT. Corol. 1. Hence CD: cd :: CR : CT. THEOREM XVIII (14). Q. R. D. The same Figure being constructed as in the last Proposition, each Ordinate will divide the Axis, and the Semi-axis added to the external Part, in the same Ratio. Corol. 1. Hence, and from cor. 3 to the last prop. it is, 2 cd2 = CD. DT = AD. DB = CD2 - CA", Corol. 2. Hence also CA2 CD2- cd2, and ca2=de2-DE2. 2 Corol. 3. Farther, because CA2: ca2:: AD. DB or cd2: DE2. therefore CA: Ca :: cd: DE. likewise CA: Ca :: CD: de. THEOREM THEOREM XIX (15). If from any Point in the Curve there be drawn an Ordinate, and a Perpendicular to the Curve, or to the Tangent at that Point: Then the Dist, on the Trans. between the Centre and Ordinate, CD: For, by theor. 2, CA2: ca2 :: AD. DB : DE2, and, by cor. 1 theor. 16, or 2 CD. DT = AD.DB; CA2: Ca2 :: TD. DC: TD. DP, THEOREM XX (18). : DP. Q. E. D. If there be Two Tangents drawn, the One to the Extremity of the Transverse, and the other to the Extremity of any other Diameter, each meeting the other's Diameter produced; the two Tangential Triangles so formed, will be equal. The two triangles CET, CAN have then the angle c common, and the sides about that angle reciprocally proportional; those triangles are therefore equal, viz. the ACET = ACAN. Q.E.D. Coro Corol. 1. Take each of the equal tri. CET, CAN, from the common space CAPE, and there remains the external A PAT = ∆ PNE. Corol. 2. Also take the equal triangles CET, CAN, from the common triangle CED, and there remains the A TED = trapez. ANED. THEOREM XXI (19). The same being supposed as in the last Proposition; then any Lines ka, GQ, drawn parallel to the two Tangents, shall also cut off equal Spaces. The three sim. triangles CAN, CDE, CGH, For, draw the ordinate DE. Then are to each other as CA2, CD, CG2; th. by div. the trap. ANED: trap. ANHG :: CD-CA2: CG2 - CA2. But, by theor. 1, DE: GQ2:: 2 :: CD2-CA2: CG2- CA2; theref. by equ.trap.ANED: trap. ANHG :: But, by sim. As, tri. TED: tri. KQG :: DE : GQ2; Corol. 1. The three spaces ANHG, TEHG, KQG are all equal. Corol. 2. From the equals ANHG, KQG, Corol. 3. And from the equals ghHG, gqQG, Corol. 4. Again, from the equals KQG, TEHG, and there remains TELK = A LQH. Corol the triangle KQG becomes the triangle IRC, Corol. 6. Also when the lines KQ and HQ, by moving with a parallel motion, come into the position се, ме, the triangle LQH becomes the triangle сeм, THEOREM XXII (20): Any Diameter bisects all its Double Ordinates, or the Lines drawn Parallel to the Tangent at its Vertex, or to its Conjugate Diameter. For, draw QH, qh perpendicular to the transverse. Then by cor. 3 theor. 21, the A LQH = A Lqh; but these triangles are also equiangular; conseq. their like sides are equal, or LQ = Lq. Corol. 1. Any diameter divides the ellipse into two equal parts. For, the ordinates on each side being equal to each other, and equal in number; all the ordinates, or the area, on one side of the diameter, is equal to all the ordinates, or the area, on the other side of it. Corol. 2. In like manner, if the ordinate be produced to the conjugate hyperbolas at o', q', it may be proved that VOL. III. C LA |