A Course of Mathematics: In Three Volumes : Composed for the Use of the Royal Military Academy ...J. Johnson, 1811 |
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Page 4
... right line . E h G A S T D C B H For when CD = CG , then also is DE = GH by cor . 2 , th . 1 . But the ∠D = ∠G , being both right angles ; therefore the third side CE = CH , and the DCE = GCH , and consequently ECH is a right line ...
... right line . E h G A S T D C B H For when CD = CG , then also is DE = GH by cor . 2 , th . 1 . But the ∠D = ∠G , being both right angles ; therefore the third side CE = CH , and the DCE = GCH , and consequently ECH is a right line ...
Page 12
... angles at P being right , and the side PE being common , the two triangles GEP , FEP are equal in all respects , and so GE = FE , and GP = FP . Therefore , since FP = FG , and FC = + Ff , and the angle at F common , the side CP will be ...
... angles at P being right , and the side PE being common , the two triangles GEP , FEP are equal in all respects , and so GE = FE , and GP = FP . Therefore , since FP = FG , and FC = + Ff , and the angle at F common , the side CP will be ...
Page 13
... right line . h K GBS C TAD H e For , when CD = CG , then also is DE = GH by cor . 2 theor . 1 . But the ∠D = ∠G , being both right angles ; therefore the third side CE = CH , and the DCE = GCH , and consequently ECH is a right line ...
... right line . h K GBS C TAD H e For , when CD = CG , then also is DE = GH by cor . 2 theor . 1 . But the ∠D = ∠G , being both right angles ; therefore the third side CE = CH , and the DCE = GCH , and consequently ECH is a right line ...
Page 33
... angles . For , let вм be drawn from в , рег- pendicularly to LM , and produced till DM = BM : join AD , and from the ... right line LM parallel to the base ; and when LM in the above figure becomes parallel to AB , since MCB = ACL ...
... angles . For , let вм be drawn from в , рег- pendicularly to LM , and produced till DM = BM : join AD , and from the ... right line LM parallel to the base ; and when LM in the above figure becomes parallel to AB , since MCB = ACL ...
Page 34
... right - angled triangles AEC ' , AEC , having AE common , we have C'E < CE * . Q. E. D. Cor . Of all isoperimetrical ... angles , the isosceles one is the greatest . • When two mathematical quantities are separated by the character ...
... right - angled triangles AEC ' , AEC , having AE common , we have C'E < CE * . Q. E. D. Cor . Of all isoperimetrical ... angles , the isosceles one is the greatest . • When two mathematical quantities are separated by the character ...
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Common terms and phrases
abscissas altitude ANHG asymptotes axis ball base beam becomes bisect CA² CD² CE² centre circle circumscribed coefficients cone conic section consequently Corol cosine CR² cubic equation curve cylinder denote determine diameter distance divided draw drawn equa equal equation expression feet find the fluent fluxion force gives greatest Hence horizontal hyperbola inches length logarithm manner measured meridian motion nearly negative ordinates parabola parallel perimeter perp perpendicular plane polygon prism prob PROBLEM proportional quadrant quantity radius rectangle resistance right angles right line roots Scholium sides sin² sine solid angle sphere spherical angle spherical excess spherical triangle spherical trigonometry square suppose surf surface tangent theor THEOREM theref tion velocity vertical weight whence whole
Popular passages
Page 63 - In any plane triangle, the sum of any two sides is to their difference, as the tangent of half the sum of the opposite angles is to the tangent of half their difference.
Page 112 - Since the exterior angle of a triangle is equal to the sum of the two interior opposite angles (th.
Page 247 - Or, by art. 3 14 of the same, the pressure is equal to the weight of a column of the fluid, •whose base is equal to the surface pressed, and...
Page 78 - A solid angle is that which is made by the meeting of more than two plane angles, which are not in the same plane, in one point. X. ' The tenth definition is omitted for reasons given in the notes.
Page 333 - ... to secure uniformity, his trees were all felled in the same season of the year, were squared the day after, and the experiments tried the 3d day.
Page 164 - Cor. 3. An equation will want its third term, if the sum of the products of the roots taken two and two, is partly positive, partly negative, and these mutually destroy each other. Remark.
Page 162 - ... preceding equation is only of the fourth power or degree ; but it is manifest that the above remark applies to equations of higher or lower dimensions : viz. that in general an equation of any degree whatever has as many roots as there are units in the exponent of the highest power of the unknown quantity, and that each root has the property of rendering, by its substitution in place of the unknown quantity, the aggregate of all the terms of the equation equul to nothing.
Page 72 - Prove that, in any plane triangle, the base is to the difference of the other two sides, as the sine of half the sum of the angles at the base, to the sine of half their difference : also, that the...
Page 259 - And when this is compared with the proportion of the velocity and length of gun in the last paragraph, it is evident that we gain extremely little in the range by a great increase in the length of the gun, with the same charge of powder. In fact the range is nearly as the 5th root of the length of the bore ; which is so small an increase, as to amount only to about a...
Page 72 - Prob. 12. How must three trees, A, B, C, be planted, so that the angle at A may be double the angle at B, the angle at B double the angle at C, and a line of 400 yards may just go round them ? Ans.