 | Charles Guilford Burnham - 1837 - 266 pages
...books purchased. Therefore — When the first and last terms, and the common difference are given, to find the number of terms : RULE. Divide the difference of the extremes by the common difference, and the quotient will be 1 less than the number of terms. 10. If the first term of a series be 2, and the... | |
 | James Thomson (LL.D.) - 1837 - 296 pages
...Answ. 38^. RULE III. The extremes and the common difference being given, to find the number of terms ; Divide the difference of the extremes by the common difference, and add a unit to the quotient. The reasons of this rule and of the next will be obvious from comparing them... | |
 | George Willson - 1838 - 194 pages
...their ages ? Ans. 2 years. PROBLEM IV. — Given the first term, last term, and common difference, to find the number of terms. RULE. — Divide the...difference of the extremes by the common difference, and the quotient increased by 1 is the number of terms. 7. A man travelling a journey, went 18 miles the... | |
 | George Willson - 1838 - 194 pages
...their ages ? Ans. 2 years. PROBLEM IV. — Given the first term, last term, and common difference, to find the number of terms. RULE. — Divide the...difference of the extremes by the common difference, and the quotient increased by 1 is the number of terms. 7. A man travelling a journey, went 18 miles the... | |
 | Frederick Emerson - 1839 - 300 pages
...increase, and also the number of miles travelled. PROBLEM in. The extremes and common difference given, to find the number of terms. RULE. Divide the difference...of the extremes by the common difference, and add 1 to the quotient; the sum will be the number of terms. The difference of the extremes divided by the... | |
 | Nathan Daboll - 1839 - 220 pages
...Ans. 22 miles 3 furlongs 100 yards. CASE IV. TAe first term, last term and common difference given, to find the number of terms. RULE. Divide the difference of the extremes by the common difference, and the quotient increased by 1, will be the number of terms. EXAMPLES. 1 . A man bought cloth in arithmetical... | |
 | Benjamin Greenleaf - 1839 - 356 pages
...to the basket ? Ans. 288090 miles, 2 rods. PROBLEM HI. Given the extremes and the common difference, to find the number of terms. RULE. Divide the difference of the extremes by the common difference, and the quotient increased by one, will be the number of terms required. 9. If the extremes are 3 and 45,... | |
 | Frederick Emerson - 1839 - 300 pages
...miles travelled. PROBLEM in. The extremes and common difference given, to find the number of term?. RULE. Divide the difference of the extremes by the common difference, and add 1 to the quotient; the sum •will be the number of terms. The difference of the extremes divided by... | |
 | Calvin Tracy - 1840 - 316 pages
...8+1=9, the whole number of terms, or answer required. From the above we derive the following rule : RULE. — Divide the difference of the extremes by...the common difference, and add one to the quotient. 2. A man commenced a journey, and traveled the first day only 4 miles ; after which he gained each... | |
 | 1841 - 200 pages
...5m. distance 366m. •«* CASE IV. Given the first term, the last term, and the common difference, to find the number of terms. RULE. — (') Divide...difference of the extremes by the common difference, and the quotient increased by one is the number of terms required. Question. — 1. The first and last... | |
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Divide the difference of the extremes by the common difference, and the quotient increased by 1 is the number of terms. 
